Question

What are the solutions for x when y is equal to 0 in the following quadratic

function?
у = х^2 + 16х + 64
ОА) х = 0
ОВ) х = 8
OC) x = -8
OD) х = 0 or x = 8
OE) х = 0 or x = -8​
I did not mean to mark this under computer, I don't know how to fix it. ugh.

Answer 1

OC) x = -8

Step-by-step explanation:

Given Equation is:

`y = x^(2) +16x+64`

Putting y=0 will give us:

`x^(2) +16x+64 = 0`

The equation is a complete square

The formula is

`a^(2)+2ab+b^(2)=(a+b)^(2)`

So,

putting in the form of formula

`(x)^(2)+ 2.x.8+(8)^(2)=0`

`(x+8)^(2) = 0`

The square will be cancelled with square root

`\sqrt{(x+8)^(2) } = 0`

`x+8 = 0`

`x = -8`

There is only one root.

So, the solution for x wheny is equal to zero is x = -8 ..