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Find f(-3) if f(x) = x 2.

User Marshalee
by
7.4k points

2 Answers

2 votes

Answer:
f(-3)=9

Explanation:

Given the quadratic function
f(x)=x^2, you can find
f(-3) by substituting the input value
x=-3 into this function, with this procedure you will get the corresponding output value.

Therefore, when
x=-3, you get that the output value is the following:


f(x)=x^2\\\f(-3)=(-3)^2

NOTE: Since the exponent is an even number, the result will be positive, because:


(-3)(-3)=3

Therefore, knowing this, you get that
f(-3) of the function
f(x)=x^(2) is:


f(-3)=9

User RunningRhetoric
by
8.7k points
2 votes

Answer:

f(-3) = 9

Explanation:

Lets define f(a) first where a is any integer,

f(a) is found out by putting the integer in the function in place of the variable

So for the given question


f(x) = x^(2)

In order to find f(-3) we will put -3 in place of x

So putting -3,


f(-3) = (-3)^(2)


f(-3) = 9

So, the value of function at -3 is 9 ..

User Kevy Granero
by
7.8k points

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