Question

A man gave out $24000 to his three brothers A,B and C to be shared among themselves . If A takes twice as much as B and B is given one third of what C takes , how much did each of them receive?​

Answer 1

A = 8000

B = 4000

C = 12000

Explanation:

$24000 = A,B and C

A = 2B

B = 1/3C

solve for the letter that gets described the most

that letter is B

A =2B

B = 1/3C -> C = 3B

24000 = A + B + C

24000 = 2B + B + 3B

24000 = 6B

B = 4000

A =2B = 8000

C = 3B = 12000

Answer 2

A = $8000
B = $4000
C = $12000

A = 2B
B = 1/3 (C)
A + B + C = $24000
SUBSTITUTE VARIABLES
2B + 1/3 C + C = $24000
2 (1/3 C) + 1/3 C + C = 24000
2/3 C + 1/3 C + C = 24000
2C = 24000
C = 12000

B = 1/3 (12000)
B = 4000

A = 2(4000)
A = 8000