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5 votes
Use a half-angled identity to find the exact value of sin 75 degrees

2 Answers

4 votes

Answer:

[A]
\frac{\sqrt{2 + √(3) } }{2}

User Danilo Teodoro
by
8.3k points
6 votes

Answer:


\sin 75\degree=\frac{\sqrt{2+√(3)}}{2}

Explanation:

The haf-angle formula is given by:


\sin (1)/(2)\theta =\sqrt{(1-\cos \theta)/(2) }


\sin 75\degree=\sin (1)/(2)(150\degree).

This implies that:


\sin (1)/(2)(150\degree) =\sqrt{(1-\cos 150\degree)/(2) }


\sin (1)/(2)(150\degree) =\sqrt{(1--(√(3))/(2))/(2)}


\sin (1)/(2)(150\degree) =\sqrt{(2+√(3))/(4)}

We simplify the square root to obtain:


\sin (1)/(2)(150\degree)=\frac{\sqrt{2+√(3)}}{2}

User Murshid Ahmed
by
8.1k points

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