Answer:

Explanation:
When launching a numerical cube there are 6 possible results
S = {1, 2, 3, 4, 5, 6}
Among these possible outcomes only 3 are even numbers
S = {2, 4, 6}
So the probability of obtaining an even number is

Then, the probability of obtaining a number other than 2 is:
.
If 2 launches are made then the events are independent,
Thus:
P(even, then not 2) is
