Question

Please Help Quickly!!!

Find the slope of the tangent line of each equation at x = 1.

y = x^2

Answer 1

It's the value of
`(\mathrm dy)/(\mathrm dx)` when
`x=1`:

`y=x^2\implies(\mathrm dy)/(\mathrm dx)=2x`

When
`x=1`, the derivative/slope is 2, so the answer is C.