Question

a container holds 136.5 of SO2 at 20.°c and 125 mmHg. what will the volume of the SO2 if the pressure is decreased to 156.7 mmHg​

Answer 1

108.9 L.

Step-by-step explanation:

• We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

• If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂).

P₁ = 125 mm Hg, V₁ = 136.5 mL,

P₂ = 156.7 mm Hg, ​V₂ = ??? mL.

∴ V₂ = (P₁V₁)/(P₂) = (125 mm Hg)(136.5 mL)/(156.7 mm Hg) = 108.9 L.