Question

39 POINTS!! ALGEBRA. PLEASE HELP, I AM FAILING AND THIS IS DUE IN AN HOUR.

Answer 1

Question 10:
`f(x)=1/2x-1` Question 13:
`f(-2)=-1` Question 11:
`f(8)=60`

Explanation:

For Question 10:

The functionis in the form of
`f(x)`. We know the slope is
`(1)/(2)` (rise 1 run 2)and the y intercept is -1 (where the line goes through the y axis). We can then put the function is slope intercept form (
`y=mx+b`) and we would have
`f(x)=1/2x-1`.

For Question 13:

To evaluate the function
`f(x)=(3)/(2) x-4` for
`f(-2)` we need to plug -2 into the function as x.
`f(-2)=(3)/(-2) (-2)-4`.
`(3)/(-2)` times -2 would equal 3 because the negatives cancle out. 3-4 equals -1 so the solution is
`f(-2)=-1`.

For question 11:

Same as question 13. plug 8 into x in
`f(x)=x^2-4`. This would be
`f(8)=(8)^2-4`. 8 squared is 64 and 64-4 is 60. Therefore
`f(8)=60`.