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Prove tha 15+17root3 is an irrational number

User Eugeneek
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1 Answer

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First of all, let's make the following observations:

15 is an integer, so in particular it is rational. The sum of two rational is rational. This means that
15+17√(3) is irrational if and only if
17√(3) is irrational.

Similarly, since 17 is rational and the multiplication of two rationals is rational, we have that
17√(3) is irrational if and only if
√(3) is irrational.

The proof that
√(3) is irrational is the following: suppose by contradiction that we could write


√(3)=(a)/(b)

where a and b are two integers with no common factors.

Squaring both sides, we have


(a^2)/(b^2)=3 \iff a^2 = 3b^2

So,
a^2 is a multiple of 3. This happens if and only if a itself is a multiple of 3. So, we can write
a=3k and the expression becomes


(3k)^2 = 3b^2 \iff 9k^2 = 3b^2 \iff 3k^2 = b^2

So,
b^2 is a multiple of 3 as well, and this happens if and only if b is itself a multiple of 3.

So, we started with the assumption that we could write
√(3) as a reduced fraction, but this assumption led to a contradiction.

We deduce that
√(3) is irrational, and so are
17√(3) and
15+17√(3)

User Olanrewaju
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