Answer:
a. 1 : 1
b. 1 : 1
Step-by-step explanation:
In this case, a heterozygous tall plant (Ty) is crossed with a homozygous short plant (yy) - which we can deduce as the recessive alleles only exhibit themselves in the absence of the dominant alleles.
The resulting offspring would have the genotypes (refer to attached image):
Ty (Tall)
Ty (Tall)
yy (short)
yy (short)
The genotypic ratio would be - 1:1 (Ty & yy are the genotypes present)
and the phenotypic ratio would be - 1:1 (tall and short are the phenotypes present)
Hope this helps