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Please. Can you help me with this problem. Thanks

Please. Can you help me with this problem. Thanks-example-1

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$3.50 and $7.25. In the movie theater the price of a drink is $3.50 and the price of a bag of pop corn is $7.25.

To solve this problem we have to use a system of equations and use a method to find the value of the unknows.

John spends a total of $61.25 on 3 drinks and 7 bags of pop corn. So, we can represent the spends as an equation of the form 3d + 7p = 61.25, where d represent drinks, p the bags of pop corn, and 61.25 the total spent.

Samuel spends a total of $107.25 on 12 drinks and 9 bags of pop corn. In the same way we can represent the spends as an equation of the form 12d + 9p = 107.25, where d represent drinks, p the bags of pop corn, and 107.25 the total spent.

Both John and Samuel spent in the same movie theater, which means both equations have a relation so we can group them into a system of equations and thus find the price of one drink and one bag of pop corn.

Writing the system of equations:


\left \{ {{3d+7p=61.25} \atop {12d+9p=107.25}} \right.

Then, we have to solve the system of equations, for this problem we going to use the substitution method which consist basically solve one of the equations for either d or p, substitute the result into the other equation, solve the new equation, and use the result to solve the other variable.

Solve the first equation for d:


d=(61.25-7p)/(3)

Substituting the result into the second equation:


12((61.25-7p)/(3))+9p=107.25

Solve the new equation for p:


p=(107.25-245)/(-19)=(137.75)/(19)=7.25

Substituting the result of the variable p in the first equation:


3d+7(7.25)=61.25

Solve the equation for d:


d=(61.25-50.75)/(3)=(10.5)/(3)=3.50

Checking the results, with d = 3.50 and p = 7.25:


\left \{ {{3(3.50)+7(7.25)=61.25} \atop {12(3.50)+9(7.25)=107.25}} \right.


\left \{ {{10.50+50.75=61.25} \atop {42+65.25)=107.25}} \right.


\left \{ {{61.25=61.25} \atop {107.25=107.25}} \right. Satisfying the equals of the system of equations.

User Claudio Bredfeldt
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