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X^3+3x^2-28x=0 where will the graph cross the x axis

1 Answer

4 votes

Answer:

x = - 7, x = 0 and x = 4

Explanation:

Factor the polynomial and solve for x

Given

x³ + 3x² - 28x = 0 ← factor out x from each term

x(x² + 3x - 28) = 0 ← factor the quadratic

x(x + 7)(x - 4) = 0

Equate each factor to zero and solve for x

x = 0

x + 7 = 0 ⇒ x = - 7

x - 4 = 0 ⇒ x = 4

These are the 3 points where the graph crosses the x- axis

User Ahmed Laatabi
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