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4 votes
A student pushes a 35-kg block on a frictionless, horizontal surface with a force of 18 N. What is the acceleration of the block ?

A. 1.0m/sSquared

B. 1.4m/sSquared

C. 1.6m/sSquared

D. 1.9m/sSquared

User Midori
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2 Answers

6 votes

Answer:

A = F/M (acceleration = force/mass)

A= 18/35 (18N is the force while 35 kg is obviously the mass)

A = 0.51...m/s^2

well thats the only way the answer could be done which seems there must be a mistake in your choices.

~batmans wife dun dun dun....

User Mingsheng
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5.8k points
2 votes

Newton wrote . . . F = m a

From that, we can derive . . . a = F/m

a = (18 N) / (35 kg)

a = 0.514... m/s^2

None of the choices says this.

Choice-D is the reciprocal of the correct answer ... the result of doing the division backwards ... m/F .

User Alessandro Romano
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5.1k points