Question

Chem help 36 and 37 the word cut off on 37 is larger​

Answer 1

• 1mol occupies 22.4L at STP

moles of Oxygen:-

• 5/22.4=0.223

Molecules of oxygen:-

• 0.223×6.022×10^23=1.343×10^23molecules

Now

Same

`\\ \rm\Rrightarrow No\:of\:moles=(1.343(10^(23)))/(6.022(10^(23)))`

`\\ \rm\Rrightarrow 0.223mol`

Volume remains same 5L

#37

• Degree of freedom of CO_2=5
• Degree of freedom of H_2=3

So velocity is more

Answer 2

The solution for problem 36 is in the picture attached. I am 80% sure it’s correct.