Answer:
3850 Hz
Step-by-step explanation:
The auditory canal is a tube open at only one end, so we can consider it as a closed tube.
The fundamental frequency in a closed tube is given by
![f_1 = (v)/(4L)](https://img.qammunity.org/2020/formulas/physics/high-school/a0q3d49y4qm5xjxhhtd7h3iyb6bgne774g.png)
where
v is the speed of sound
L is the length of the tube
Here we have
v = 348 m/s
L = 2.26 cm = 0.0226 m
So the fundamental frequency is
![f=(348 m/s)/(4(0.0226 m))=3,850 Hz](https://img.qammunity.org/2020/formulas/physics/college/ewchuq3m297b2e2ja62ksgtxmg9a64bqho.png)