Answer:
![\$11.13](https://img.qammunity.org/2020/formulas/mathematics/high-school/ywhdkzyj5wnhe7zee8f19wbfbl9i017yni.png)
Explanation:
step 1
Find the surface area of the cylinder
The surface area of the cylinder is equal to
![SA=\pi r^(2) +2\pi rh](https://img.qammunity.org/2020/formulas/mathematics/high-school/pw7xxiqwqepfxfftb8hjavjqv2kznvxv6l.png)
we have
----> the radius is half the diameter
![h=5\ in](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xhy88uem0840wbzvnu9k1ne7r2j907rbnb.png)
assume
![\pi =3.14](https://img.qammunity.org/2020/formulas/mathematics/high-school/595myhvi9x0vjp0b1ku7bsoelmk1x8jihg.png)
substitute
![SA=(3.14)(1.5)^(2) +2(3.14)(1.5)(5)=54.165\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zjejxvtg13075v73akjikfpkl3fa2fr3ux.png)
Find the cost
![54.165*(0.75)=\$40.62](https://img.qammunity.org/2020/formulas/mathematics/high-school/yarxnb51a6h8hi0cbadcgkzx8hdymngu4b.png)
step 2
Find the surface area of the square prism
The surface area of the prism is equal to
![SA=b^(2) +4bh](https://img.qammunity.org/2020/formulas/mathematics/high-school/98d2qvnh40f7d83td2df3mn5l8sf8uuyle.png)
we have
![h=5\ in](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xhy88uem0840wbzvnu9k1ne7r2j907rbnb.png)
substitute
![SA=(3)^(2) +4(3)(5)=69\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4cwdxmvgyrqx763g1vgso0z66ow90b37fu.png)
Find the cost
![69*(0.75)=\$51.75](https://img.qammunity.org/2020/formulas/mathematics/high-school/zbazqy5sbs7sxuei9ukuvgbegnw1sijkpx.png)
step 3
Find the difference of costs
![\$51.75-\$40.62=\$11.13](https://img.qammunity.org/2020/formulas/mathematics/high-school/p8pvrc4viacvb0yhyw2zp3e7u2rujj0koh.png)