Answer: 7. y = 2 sin (2x) - 3
![\bold{8.\quad y=sin\bigg(8x + (8)/(\pi)\bigg)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/mb19uew6g3wb3f7mzhh9m8yxs09zmjaken.png)
Explanation:
The general form of a sine equation is: y = A sin (Bx - C) + D where
- Amplitude = |A|
- Period (P) =
![(2\pi)/(B)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3rxjf4596ohi7m7q3iicrbejdg65ngohdq.png)
- Phase Shift =
![(C)/(B)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c2jnoos7q9faywvb1a1rg5n5h6g56xn5zu.png)
- Vertical Shift = D (positive is up, negative is down)
7. Given:
- A = 2
- P = π =
→ B = 2 - C = 0 (none)
- D = -3
--> y = 2 sin (2x) - 3
8. Given:
- A = 1
- P =
=
→ B = 8
![\text{Phase Shift = }-\pi = (C)/(8)\implies C = -8\pi](https://img.qammunity.org/2020/formulas/mathematics/high-school/ejk7ihm1bopf6hns1yoqh0lnae9n2d596e.png)
- D = 0 (none)
![\implies y=sin\bigg(8x + (8)/(\pi)\bigg)](https://img.qammunity.org/2020/formulas/mathematics/high-school/xcy0h9kigm7e1iohzkli7p728osore52cm.png)