Question

if a gas with a pressure of 5 atmospheres cooled from 500 K to 250 K, then what is its final pressure?

Answer 1

The answer is in the photo.

Answer 2

Solution is here,

initial pressure(P1)=5 atm

initial temperature(T1)=500K

final pressure(P2)=?

final temperature(T2)=250K

now from Charle' law of gas,

P1/P2 =T1/T2

or, 5/P2 =500/250

or, 5/P2 = 2

or, P2=5/2

or, P2=2.5 atm