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Calculate the height of a column of ethylene glycol (CH(OH)CH(OH)) that would be supported by
atmospheric pressure. The density of ethylene glycol is 1.112 g/cm

Answer 1

`\boxed{\text{9.170 m}}`

Step-by-step explanation:

The pressure p exerted by a column of liquid is given by the formula

p = hρg

where

h = height of column

ρ = density of liquid

g = acceleration due to gravity

Data:

p = 1 bar = 100 kPa = 10⁵ N·m⁻² = 10⁵ kg·m⁻¹s⁻²

ρ = 1.112 g·cm⁻³ = 1112 kg·m⁻³

g = 9.807 m·s⁻²

Calculation:

10⁵ = h × 1112 × 9.807

10⁵ = 1.091 × 10⁴ h

h = 9.170 m

`\text{The height of a column of ethylene glycol that would be supported by an}\\\\\text{atmospheric pressure of 1 bar is }\boxed{\textbf{9.170 m}}`