Question

At a temperature of 500 kelvins, 6 liters of an ideal gas had a pressure of 300 newtons

per square meter. If the temperature was reduced to 250 kelvins, and the volume raised
to 9 liters, what was the resulting pressure ?
(A) 100 newtons/m^2
(B) 150 newtons/m^2
(C) 450 newtons/m^2
(D) 900 newtons/m^2
(E) none of these

Answer 1

Answer A

Step-by-step explanation:

Answer 2

(A) 100 newtons/m^2

Step-by-step explanation:

Hello,

In this case, the equation defining such changes is:

`P_1V_1T_2=P_2V_2T_1`

Thus, the unknown is the pressure at the second state, which is found as shown below:

`P_2=(P_1V_1T_2)/(V_2T_1)=(300Pa*6L*250K)/(9L*500K) \\P_2=100Pa=100(N)/(m^2)`

Therefore, the answer is (A).

Best regards.