Answer:
Option B is right.
Explanation:
Given that an artist designed a badge for a school club.
ABCD is given in the picture.
AD =
![√((-7+8)^2 +(7-5)^2) \\=√(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uk1sj47poc369btplj1a2sr9oy5w8xdq4z.png)
If JKLM is enlargement of ABCD, then scale factor would b the ratio of AD to JM
JM =
![√((5-2)^2+(4+2)^2) \\=√(45) \\3√(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/stogf2ahhsqx9ldbguusr76qnnfjstxksh.png)
Scale factor = 3
AB = 3 hence JK = 9
DC = 1 and so ML = 3
ML is parallel to x axis with a distance of 3 units.
COordinates of L = (5+3, 4) = (8,4)
Option B is right