Simplify (x^(2) + 3x - 4) + (4^(2) - 5) - (7x + 3) ​

Question

Simplify


`(x^(2) + 3x - 4) + (4^(2) - 5) - (7x + 3)`
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Answer 1

First you want to drop the parenthesis. If there is a “+” sign, you do not have to change anything. If there is a “-“ sign, you have to distribute the negative in order to simplify, so imagine you are distributing -1 to 7x + 3 to make it -7x -3.

So, you now have x^2 + 3x - 4 + 16 -5 - 7x -3. (I evaluated the 4^2 to 16)

Now, what you want to do now is to combine like terms. Notice that there is only one x^2, so it is the same. There are two terms that have “x”. 3x and -7x react like normal numbers and they form -4x. The numbers who don’t have x on them you combine like terms.

Answer is x^2 - 4x - 12

Answer 2

X^2-4x+4 is the answer, to save you points next time, use an app called M8thw8y