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PLEASE HELP!!! Solve -(6)^x-1+5=(2/3)^2-x by graphing. Round to the nearest tenth.

X = 1.8 <--- ANSWER

PLEASE HELP!!! Solve -(6)^x-1+5=(2/3)^2-x by graphing. Round to the nearest tenth-example-1
User BeS
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1 Answer

7 votes

Answer:

x= 1.8

Explanation:

We have been given the equation;

-(6)^(x-1)+5=(2/3)^(2-x)

We are required to determine the value of via graphing. To do this we can split up the right and the left hand sides of the equation to form the following two separate equations;

y = -(6)^(x-1)+5

y = (2/3)^(2-x)

We then proceed to graph the two equations on the same graph. The solution will be the point where the equations will intersect. Find the attachment below for the graph;

The value of x is 1.785. To the nearest tenth we have x = 1.8

PLEASE HELP!!! Solve -(6)^x-1+5=(2/3)^2-x by graphing. Round to the nearest tenth-example-1
User Azzi
by
5.2k points
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