Question

What is the first four terms of 3n²

Answer 1

Suppose there is a function
`f(n)=3n^2, n\in\mathbb{N}`.

We start counting by 1 from the first element in domain of natural numbers so: 1, 2, 3, 4.

We assemble the definition set
`A=\{1,2,3,4\}` than use the function f(n) to create transformation set:

`f(A)=3\{1,2,3,4\}^2\Longrightarrow\{3,6,9,12\}^2 \\</p><p>\boxed{B=\{9,36,81,144\}}</p><p>`

So the first four terms are defined in transformation set B.

Hope this helps.

r3t40