55.6k views
0 votes
A 15.7 g aluminum block is warmed to 53.6 ∘C and plunged into an insulated beaker containing 32.1 g of water initially at 24.2 ∘C. The aluminum and the water are allowed to come to thermal equilibrium.

Assuming that no heat is lost, what is the final temperature of the water and aluminum?

User Prosoitos
by
5.7k points

1 Answer

0 votes

Answer:

27.055 (°C)

Step-by-step explanation:

the final temperature of the water and the aluminium has the same value: the aluminium block lost the heat, the water 'takes' the heat.

All the details are in the attached picture, the answer is marked with green.

A 15.7 g aluminum block is warmed to 53.6 ∘C and plunged into an insulated beaker-example-1
User Levenal
by
5.4k points