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A water sprinkler rotates in a circular pattern witha radius of 8 feet. if the sprinkler stops 60 degrees short of completing the circular patterns, which is closest to the distance of the outer are that is not getting sprinkled with water

a.4.19 ft
b.8.37ft
c.41.87ft
d.50.24ft

User Aphid
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1 Answer

2 votes

Answer:

B. 8.37 ft

Explanation:

⇒This question is on circumference

⇒The water sprinkler covers a circular pattern as it moves to cover 300° and remain with 60° to cover so as to complete a single circular pattern.

⇒The remaining distance asked is the one represented by 60°

⇒Apply the formula for circumference of a circle with angle theta


c=2\pi r\alpha/360 where alpha is the angle in degrees

Given that r=8ft and ∝=60°

c=3.14×2×8×60°/360°

c=8.37 ft

User Rstudent
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