Question

4-2(6x-5)=-4 solve for x​

Answer 1

`\large\boxed{x=(3)/(2)}`

Explanation:

`4-2(6x-5)=-4\qquad\text{subtract 4 from both sides}\\\\-2(6x-5)=-8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(-2)(6x)+(-2)(-5)=-8\\\\-12x+10=-8\qquad\text{subtract 10 from both sides}\\\\-12x=-18\qquad\text{divide both sides by (-12)}\\\\x=(-18\!\!\!\!\!\diagup^3)/(-12\!\!\!\!\!\diagup_2)\\\\x=(3)/(2)`

Answer 2

`\boxed{ x = (3)/(2)}`

Explanation:

`\begin{array}{rcll}4 - 2(6x - 5) & = & -4 &\\- 2(6x - 5) & = & -8 &\text{Subtracted 4 from each side}\\6x - 5 & = & 4 &\text{Divided each side by -2}\\6x & = & 9 &\text{Added 5 to each side}\\x & = &\mathbf{(3)/(2)} &\text{Divided each side by 6}\end{array}`

Check:

`\begin{array}{rlc}4 - 2(6*(3)/(2) - 5)& = &-4\\4 - 2(9 - 5) & = & -4\\4 - 2*4 & = & -4\\4 - 8 & = & -4\\-4 & = & -4\\\end{array}`