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Calculate the number of grams of carbon dioxide produced from 6 moles of oxygen gas. List only the number of grams of carbon dioxide C6H10+o2 Co2+h2o

User Bojana
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Answer:


\boxed{\text{190 g}}

Step-by-step explanation:

We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r: 44.01

2C₆H₁₀ + 17O₂ ⟶ 12CO₂ + 10H₂O

n/mol: 6

1. Use the molar ratio of CO₂:O₂ to calculate the moles of CO₂.


\text{Moles of CO$_(2)$ = 6 mol O$_(2)$}  * \frac{\text{12 mol CO$_(2)$}}{\text{17 mol O$_(2)$}} =\text{4.24 mol CO$_(2)$}

2. Use the molar mass of CO₂ to calculate the mass of CO₂.


\text{Mass of CO$_(2)$ = 4.24 mol CO$_(2)$} * \frac{\text{44.01 g CO$_(2)$}}{\text{1 mol CO$_(2)$}} = \text{190 g CO$_(2)$}\\\\\text{The reaction will produce }\boxed{\textbf{190 g}}\text{of CO}_(2)

User JOshT
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