Question

1) Find f(x) if it is known that f(5a)=5a−2.
2) Find g(x) if it is known that g(2t)=8t−1.

Answer 1

1)for the first one you can put a=(1/5)a in the function and it will be:

`f(a) = a - 2`

so in a function , alphabet is not important and you can rewrite it to this:

`f(x) = x - 2`

2)the same as the first , we can put t=(1/2)t and conclusion is :

`g(t) = 4t - 1`

and then change the t to x:

`g(x) = 4x - 1`

Answer 2

Explanation:

One

f(5a) means that wherever you see an x, you put in 5a

x = 5a

f(x) = x/5t * 5t - 2

f(x) = x - 2

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Two

g(2t) = 8t - 1

x = 2t

g(x) = 8t/2t*x - 1

g(x) = 4x - 1