we know in these kind of triangles that have a 90 degrees angle, we can do:
![{a}^(2) + {b}^(2) = {c}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h2ipwfp86vksr8637t9a311u2unct0bo00.png)
so the first question:
![\sqrt{ {99}^(2) + {20}^(2) } = 101](https://img.qammunity.org/2020/formulas/mathematics/high-school/c7dhlecjg6lyieei82o4jsombkhbas1af2.png)
and then:
![b = \sqrt{ {17}^(2) - {15}^(2) } = 8](https://img.qammunity.org/2020/formulas/mathematics/high-school/cinp1s1qsrirqf0se1io5gasc5fn37yqrl.png)
so , when you want to rationalize , usually you must multiply the irrational factor as 1:
![( √(15) )/( √(15) ) = 1](https://img.qammunity.org/2020/formulas/mathematics/high-school/i1nblszjgcu3egiuh0agwbt8smnuub26dj.png)
so , now multiply:
![(3)/( √(15) ) * ( √(15) )/( √(15) ) = (3 √(15) )/(15) = ( √(15) )/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/z6drcg2mvkip9aw56v1xnn1cwcdlroetr7.png)
in the next question,we know negative numbers in radical don't have any solution so 2 is correct,