Question

a hydraulic pressa has piston of cross sectional area 2.5m² and piston B of cross section area 5m².if a force of 20N is applied at piston A what force is bring lifted​

Answer 1

Given,

for piston A,

Area(A1)=2.5 m^2

Force(F1)= 20N

for piston B,

Area(A2)=5m^2

Force(F2)=?

We have,

pressure at piston A=pressure at piston B

or, P1=P2

or, F1/A1 =F2/A2

or, 20/2.5 = F2/5

or, F2=40 N