Answer:
the zeros are x ∈ {-3, 1/2, 2}
Explanation:
A graphing calculator shows where the zeros are. (See attached)
These suggest factors of (x +3)(x -2)(2x -1). To verify these are the factors, we can multiply this out to get ...
= (x^2 +x -6)(2x -1)
= 2x^2 +2x^2 -12x -x^2 -x +6
= 2x^3 +x^2 -13x +6 . . . . same as the original expression