Question

Does the midpoint BC lie on line AG? Why or why not?

Answer 1

D

Explanation:

Answer 2

see below

Explanation:

Put the (x, y) values of point F into the equation for line AG and see if they work:

y = (b/(a+c))x

For (x, y) = (a+c, b), this is ...

b = (b/(a+c))(a+c) = b·(a+c)/(a+c) = b·1 = b . . . . . a true statement

Yes, F lies on line AG.