Answer:
- The molar concentraion is 0.74 M
Step-by-step explanation:
1) Data:
a) % w/v = 2.5%
b) compound: H₂O₂ (from a table molar mass = 34.0147 g/mol)
c) M = ?
2) Formulae:
a) % w/v = (mass of soulte / volume of solution) × 100
b) numer of moles, n = mass in grams / molar mass
c) M = number of moles of solute / liters of solution
3) Solution:
a) Take a base of 100 ml of solution (0.100 liter):
- %w/v = 2.5% = 2.5 g solute / 100 ml solution
- mass of solute = 2.5 g / 100 ml × 100 ml = 2.5 g
b) Calculate the number of moles of solute, n:
- n = mass in grams / molar mass = 2.5 g / 34.0147 g/mol = 0.0735 mol
c) Calculate the molarity, M:
- M = n / V in liter = 0.0735 mol / 0.100 liter = 0.735 M
Round to two significant figures: 0.74 M ← answer