The surface area of a right cone which has a base diameter of six units and a height of eight units is:

Question

asked Apr 6, 2020 1.8k views

2 Answers

Kamil Mikolajczyk · Answer 1 · 2020-04-07T05:01:36+0000

Answer:

SA=108.8 units^2

Explanation:

The surface area of a right cone is given by

$S.A=\pi r^2+\pi rl$

The relation between the slant height l, the radius r, and the height h, is

l^2=r^2+h^2

l^2=3^2+8^2

l^2=9+64

l^2=73

l=√(73)

$S.A=\pi * 3^2+\pi *3*√(73)$

SA=108.8 units^2

JSilv · Answer 2 · 2020-04-10T05:12:46+0000

Answer:
$A = 108.80\ units^2$

Explanation:

The surface area of right cone is calculated by the following formula

$A = \pi r *√(r^2 +h^2)+\pi r^2$

Where r is the radius of the cone and h is the height

In this case we know that the diameter d of the base is:

d=2r

So the radius is:

$r=(d)/(2)\\\\r=(6)/(2)\\\\r=3\ units$

and

$h=8\ units$

So the area is:

$A = \pi*3 *√(3^2 +8^2)+\pi(3)^2$

$A = 108.80\ units^2$