Answer:
B. √{x} + √{x - 1}
Explanation:
As hinted in the question, we have to simplify the denominator.
To understand it easier, let's imagine we have x - y in the denominator. If we multiply it with x + y we'll get x² - y², right? Check the next line:
(x - y) (x + y) = x² + xy -xy - y² = x² - y²
If we have the square of those nasty square roots, it will be much simpler to deal with. So, let's multiply the initial fraction using x+y, but with the real values:
![(1)/(√(x) - √(x - 1) ) * (√(x) + √(x - 1))/(√(x) - √(x - 1)) = (√(x) + √(x - 1))/((√(x) )^(2) - (√(x - 1) )^(2) )](https://img.qammunity.org/2020/formulas/mathematics/high-school/vt57lx7gny0f7l2qd78cbbhxs3a1e5nbff.png)
Then we simplify:
![(√(x) + √(x - 1))/((√(x) )^(2) - (√(x - 1) )^(2) ) = (√(x) + √(x - 1))/((x) - (x - 1) ) = (√(x) + √(x - 1))/( 1 )](https://img.qammunity.org/2020/formulas/mathematics/high-school/pwd2t8blz8dg07lgkpwmf14p63z3f9e7w4.png)
So, the answer is B. √{x} + √{x - 1}