Question

Please!!! Help!!

Let ​ f(x)=x2−4x−32 ​ .

Enter the x-intercepts of the quadratic function in the boxes.

Answer 1

well the intercepts are (8,0) and (-4,0) its a lot of math so you need to find it i would show you but i have a quiz

im not sure tho soo

Answer 2

The x-intercepts of the quadratic function are 8 and -4.

Explanation:

The given function is

`f(x)=x^2-4x-32`

Equate the function f(x) equal to 0, to find the x-intercepts of the quadratic function.

`f(x)=0`

`x^2-4x-32=0`

The middle term can be written as -8x+4x.

`x^2-8x+4x-32=0`

`x(x-8)+4(x-8)=0`

Take out the common factors.

`(x-8)(x+4)=0`

Using zero product property,

`x-8=0\Rightarrow x=8`

`x+4=0\Rightarrow x=-4`

Therefore the x-intercepts of the quadratic function are 8 and -4.