Question

At 400 K and a pressure of 600 mm Hg, a sample of nitrogen gas has a volume of 32.0

ml. What volume does the gas occupy at 200 K and 1.1 atm?​

Answer 1

1.546 L.

Step-by-step explanation:

• We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

• If n is constant, and have different values of P, V, and T:

(P₁V₁T₂) = (P₂V₂T₁)

P₁ = 600.0 mmHg/760 = 0.789 atm, V₁ = 4.31 L, T₁ = 400 K.

P₂= 1.1 atm, V₂ = ??? L, T₂ = 200 K.

∴ V₂ = (P₁V₁T₂)/(P₂T₁) = (0.789 atm)(4.31 L)(200 K)/(1.1 atm)(400 K) = 1.546 L.