Answer:
4.1 seconds to the nearest tenth.
Explanation:
The vertical component of the velocity = 35 sin 4.935 m/s.
The relation between the height (h) of the projectile and time is given by:
h = ut + 1/2 g^2 where u = initial velocity, t = the time and g = acceleration due to gravity which we can take to be 9.8 m/s/s. When the projectile hits the ground h = 0 .
So we have h = 35sin35 t - 4.9t^2 = 0
t(35sin35 - 4.9t) = 0
4.9t = 35 sin35
t = 35 sin 35 / 4.9
= 4.097 seconds