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Solve the Equation
2x-3=14
-x+3y=-6

1 Answer

3 votes

Explanation:

If you lost "y" in the first equation.


\underline{+\left\{\begin{array}{ccc}2x-3y=14\\-x+3y=-6\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad x=8\\\\\text{Put the value of x to the first equation:}\\\\2(8)-3y=14\\16-3y=14\qquad\text{subtract 16 from both sides}\\-3y=-2\qquad\text{divide both sides by (-3)}\\y=(2)/(3)\\\boxed{x=8,\ y=(2)/(3)}

If first equation is correct.


2x-3=14\qquad\text{add 3 to both sides}\\2x=17\qquad\text{divide both sides by 2}\\x=8.5\\\\\text{Put the value of x to the second equation:}\\-8.5+3y=-6\qquad\text{add 8.5 to both sides}\\3y=2.5\qquad\text{divide both sides by 3}\\y=(2.5)/(3)\\y=(25)/(30)\\y=(5)/(6)\\\\\boxed{x=8.5,\ y=(5)/(6)}

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