Question

Find the roots of parabola given by the following equation

Answer 1

3/2

-3

Explanation:

here

Answer 2

`x = \frac32, x = -3`

Explanation:

Hello!

We have to solve for x by using the quadratic formula.

Standard form of a quadratic:
`ax^2 + bx + c = 0`

Quadratic Formula:
`x = (-b\pm√(b^2 - 4ac))/(2a)`

First, convert it into standard form:

• 
  `2x^2 + 5x - 9 = 2x`
• 
  `2x^2+3x - 9 = 0`

Given our equtaion:
`2x^2+3x - 9 = 0`

• a = 2
• b = 3
• c = -9

Plug it into the formula and solve.

Solve

• 
  `x = (-b\pm√(b^2 - 4ac))/(2a)`
• 
  `x = (-3\pm√(3^2 - 4(2)(-9)))/(2(2))`
• 
  `x = (-3\pm√(9 +72))/(4)`
• 
  `x = (-3\pm√(81))/(4)`
• 
  `x = (-3\pm9)/(4)`
• 
  `x = \frac32, x = -3`

The roots are 1.5 and -3.