Question

Write the equation 8y = x – 0.8 in standard form. Identify A, B, and C.

480x + 5y = –48 where A = 480, B = 5, and C = 96

480x – 1y = –48 where A = 480, B = –5, and C = 96

5x – 480y = 48 where A = 5, B = –480, and C = 96

1x + 96y = 9.6 where A = 1, B = –96, and C = 0.8

Answer 1

`5x-40y=4`

Explanation:

we know that

The standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers

In this problem we have

`8y=x-0.8`

Multiply by 5 both sides

`40y=5x-4`

Adds both sides 4

`40y+4=5x`

Subtract 40y both sides

`4=5x-40y`

Rewrite

`5x-40y=4` ----> equation of the line into standard form

A=5

B=-40

C=4