Question

A substance has a specific heat of point 870JGC it requires 2000.0 J to increase the temperature of the 10 g of the substance from its original temperature to it's final temperature by how many degrees did the substance increase

Answer 1

`229.9^(\circ) C`

Step-by-step explanation:

The increase in temperature of a substance is given by

`\Delta T = (Q)/(m C_s)`

where

Q is the amount of heat absorbed by the substance

m is the mass of the substance

Cs is the specific heat capacity

In this problem,

Q = 2000.0 J

m = 10 g

Cs = 0.870 J/gC

Substituting, we find the increase in temperature:

`\Delta T = (2000.0 J)/((10 g)(0.870 g/JC))=229.9^(\circ) C`