9514 1404 393
Answer:
yes
Explanation:
We can substitute the proposed solution values and see if the inequality is true.
0.50x +0.80y ≥ 20
0.50(20) + 0.80(32) ≥ 20
10 + 25.6 ≥ 20
35.6 ≥ 20 . . . . . . true; (20, 32) is a solution
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