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What values of b satisfy 3(2b + 3)^2 = 36?
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5 votes
What values of b satisfy 3(2b + 3)^2 = 36?

User Sergey Fedorov
by
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2 Answers

5 votes

Answer:

3(2b+3)^2=36

(2b+3)^2=12

2b+3=+2 radical3

2b+3= 2 radical 3

b=- radical 3 -3 over 2

b= radical 3- 3 over 2

b=- radical 3 - 3 over 2

User Fanis Hatzidakis
by
7.2k points
3 votes

Answer:

The answer is A

Explanation:

User MARIO MORENO
by
7.0k points
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