Question

Ifa truck starts from rest and it has acceleration of 4 m/s for 5 second

calculate its final velocity. What will be the distance travelled by the track
during the time interval?
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Answer 1

Distance 50m

final velocity 20ms^-1

`s = ut + (1)/(2) a {t}^(2) \\ = 0 * t + (1)/(2) * 4 * {5}^(2) = 50m`

`v = u + at \\ v = 0 + 4 * 5 \\ v = 20ms^( - 1)`