Question

Find x and h in this trinomial right angle

Answer 1

Explanation:

Set up the Pythagorean Equation for the two triangles

x^2 + h^2 = 4^2 = 16

(x + 6)^2 + h^2 = 8^2 = 64

x^2 + h^2 = 16 Subtract. That will get rid of h^2

(x + 6)^2 - x^2 = 64 - 16 Expand the brackets. combine the right.

x^2 + 12x+36 - x^2 = 48 Combine

12x + 36 = 48 Subtract 36 from both sides

12x +36 -36 = 48-36 Combine

12x = 12 Divide by 12

12x/12 = 12/12

x = 1

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x^2 + h^2 = 4^2

1^2 + h^2 = 16

h^2 = 15

h = sqrt(15)