Question

Factor this expression completely. 6x^2 - 13x - 28

Answer 1

your answer to this question would be (3x+4) (2x-7)

Answer 2

`(2x-7)(3x+4)`

Step-by-step explanation

The given expression is:

`6{x}^(2) - 13x - 28`

We find ac=6×-28=-168

Two factors of -168 that, if added will give us -13 are 8 and -21

We split the middle term to obtain,

`6{x}^(2) + 8x - 21x- 28`

We now factor by grouping to obtain:

`2x(3x + 4) - 7(3x + 4)`

Factor further to obtain;

`(2x-7)(3x+4)`