Question

If t>0 and t2−25=0, what is the value of t?

Answer 1

Final answer is
`t=5`.

Explanation:

Given equation is
`t^2-25=0`.

Now we need to solve that equation for t when
`t>0`.

`t^2-25=0`

`t^2-5^2=0`

`(t+5)(t-5)=0`

or
`(t+5)=0`,
`(t-5)=0`

or
`t+5=0`,
`t-5=0`

or
`t=-5`,
`t=5`

Given that t>0

so that means t=-5 is not possible.

Hence final answer is
`t=5`.