Answer:
![\boxed{\text{922 mL}}](https://img.qammunity.org/2020/formulas/chemistry/middle-school/rb72v6cm8vena48c5s1nf735x834pvczrt.png)
Step-by-step explanation:
The pressure is constant, so we can use Charles' Law to calculate the volume.
![(V_(1))/(T_(1)) = (V_(2))/(T_(2))](https://img.qammunity.org/2020/formulas/chemistry/high-school/bdyz7g8k5wgoi5hd7omsjz10soblsohi1m.png)
Data:
V₁ = 693 mL; T₁ = 45 °C
V₂ = ?; T₂ = 150 °C
Calculations:
(a) Convert temperature to kelvins
T₁ = ( 45 + 273.15) = 318.15 K
T₂ = (150 + 273.15) = 423.15 K
(b) Calculate the volume
![( 693)/(318.15) = ( V_(2))/(423.15)\\\\2.178 = ( V_(2))/(423.15)\\\\V_(2) = 2.178 * 423.15 = \boxed{\textbf{922 mL}}](https://img.qammunity.org/2020/formulas/chemistry/middle-school/4wewaominbzjqbe0dzfcgbj15vdv334bq2.png)